Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
12825$
Step-by-step explanation:
1 yard = 3 ft
we can convert each of the lengths from ft to yards
240 ft = 80 yards
285 ft = 95 yards
450 ft = 150 yards
150+150+95+80 = 475 yards
1 yard of fencing costs 27$ so we are going to multiply that by the total yards
475*27=12825$
Answer:
x=9/4
Step-by-step explanation:
Not sure if it's one of the answer you listed.
The • means multiplication, so it would be
54 times 58, which equals 3,132.
2,2 is 3,4 away from 5,6 and 3²+4²=25=5² so CD=5
