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Sedbober [7]
3 years ago
15

Please help with my math

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0
$1.44

each one cost 0.24
0.24 x 6 = 1.44
harina [27]3 years ago
3 0

Answer:

your answer would be 1.44

Step-by-step explanation:

you would do

$0.96 divided by 4 is 0.24

0.24 times 6 is 1.44

 

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Find the 10th term in the Arithmetic Sequence -2, -5, -8, -11
Inessa [10]
As you can tell, the next time decreases by three every time. So, the tenth term would be -29.
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4 0
2 years ago
Consider the function ​f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0
dybincka [34]

I suppose you mean

f(x)=\cos(x^2)

Recall that

\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}

which converges everywhere. Then by substitution,

\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}

(starting at n=1 because the summand is 0 when n=0)

b. Naturally, the differentiated series represents

f'(x)=-2x\sin(x^2)

To see this, recalling the series for \sin x, we know

\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}

Multiplying by -2x gives

-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}

and from here,

-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}

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c. This series also converges everywhere. By the ratio test, the series converges if

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3 0
3 years ago
What is the product of the polynomials below?
Alexeev081 [22]
Hope this helps you.

5 0
3 years ago
A test driver has to drive a car on a 1-mile track for two rounds in a way, that his average speed is 60 mph. On his first round
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(40+x)/2=60

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3 0
2 years ago
Lisa solved 3x2 + 1 = 28 as shown.
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x squared = 9  NOT x

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4 0
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