Question

Graph the function in the interval from 0 to 2Π y = −2 sin(θ − π3) + 2

Answer 1

Answer with explanation:

The given trigonometric function is

   $y= -2 \sin (\Theta -\frac{\pi}{3})+2\\\\y= -[-2 \sin (\frac{\pi}{3}-\Theta)]+2\\\\ y=2 \sin (\frac{\pi}{3}-\Theta)+2$

The sine function has maximum and minimum are 1 and -1, which it will achieve at ,

  $\Theta =\pm(2k+1)\frac{\pi}{2}$

So, the given function will attain maximum and minimum  at,

    $=\pm(2k+1)\frac{\pi}{2}-\frac{\pi}{3}$

for different values of k.

Answer 2

Hello,
Please, see the attached file.
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