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3 years ago

H(x)=3-1/4x, find h(-8)

Mathematics

2 answers:

choli [55]3 years ago

8 0

Let's solve for H =3 -1/4 x there you go hope I helped

Masteriza [31]3 years ago

5 0

this is a function and h(x) is like a y in the equation (a variable)

when they say find h(-8) in h(x), you sub -8 into the x in the function

so h(-8) = 3-1/4(-8) = 3-(-2) = 5

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Which of the following number lines and solution sets show the values of r that make the inequality -2r+3<9 true

scoray [572]

Answer:

"Solving'' an inequality means finding all of its solutions. A "solution'' of an inequality is a number which when substituted for the variable makes the inequality a true statement. When we substitute 8 for x, the inequality becomes 8-2 > 5. Thus, x=8 is a solution of the inequality.

Step-by-step explanation:

Example 1:

Consider the inequality

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The basic strategy for inequalities and equations is the same: isolate x on one side, and put the "other stuff" on the other side. Following this strategy, let's move +5 to the right side. We accomplish this by subtracting 5 on both sides (Rule 1) to obtain

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after simplification we obtain

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Once we divide by +2 on both sides (Rule 3a), we have succeeded in isolating x on the left:

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or simplified,

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All real numbers less than 1 solve the inequality. We say that the "set of solutions'' of the inequality consists of all real numbers less than 1. In interval notation, the set of solutions is the interval tex2html_wrap_inline187 .

Example 2:

Find all solutions of the inequality

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Let's start by moving the ``5'' to the right side by subtracting 5 on both sides (Rule 1):

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or simplified,

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How do we get rid of the ``-'' sign in front of x? Just multiply by (-1) on both sides (Rule 3b), changing " tex2html_wrap_inline201 " to " tex2html_wrap_inline203 " along the way:

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or simplified

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All real numbers greater than or equal to -1 satisfy the inequality. The set of solutions of the inequality is the interval tex2html_wrap_inline205 .

Example 3:

Solve the inequality

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Let us simplify first:

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There is more than one route to proceed; let's take this one: subtract 2x on both sides (Rule 1).

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and simplify:

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Next, subtract 9 on both sides (Rule 1):

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simplify to obtain

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Then, divide by 4 (Rule 3a):

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and simplify again:

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It looks nicer, if we switch sides (Rule 2).

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In interval notation, the set of solutions looks like this: tex2html_wrap_inline227 .

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2 years ago

Can someone please help on 11&12?

Svet_ta [14]

# 12 should be the last one

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3 years ago

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lilavasa [31]

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Step-by-step explanation: j

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3 years ago

You need to buy 200 treats for a party. You can buy cookies at $ 0.80 each or muffins at $1.60 each. Your goal is to spend $200

Agata [3.3K]

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4 0

3 years ago

write the restrictions that should be imposed on the variable for each of the following function. then find, explicitly, the dom

matrenka [14]

By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1 b) p≤1/2 c) s>-1.

I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1) b) g(p)=√(1-2p) c) m(s)= (s^2+4s+4)/√(s+1)

Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.

a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.

b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.

c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.

Learn more about square root here:

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2 years ago