A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence
every time it is turned on. What is the probability that all the lights will be switched on?
2 answers:
The chance that any given bulb is on is equal to 1/2. The chance that all twenty bulbs are on at the same time is
Answer: 1/1048576 C for Plato!
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Answer:
Make it 15 squares every side
Because 1 mm is 2 squares then 7.5mm is 15 squares
Switch sides
Abc=d
Now divide both sides by bc to get a .
A= d/bc
2 x 10 4th power - 7 3rd power
2 x 10,000 - 343
20,000 - 343
19,657
I think this is the answer to your problem. Hope this helped!
-TTL
(4, -4) is the answer
-45<span>° is in quadrant IV and the point (4, -4) is the only point out of the points given that is also in quadrant IV</span>
I can’t understand your speaking a different laungue do u speak English?
