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3 years ago

How are dialations and rotations simalar?

Mathematics

1 answer:

zheka24 [161]3 years ago

7 0

Dilation and rotations are similar because they both have to move and both have one mane shop as starting point.

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Help me please

GrogVix [38]

Answer:

What is the question?

Step-by-step explanation:

3 0

3 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

Find the sum of -6/ab + a^2/b^2

Ymorist [56]

Answer:

$\frac{1}{ab^{2} }$ (a³ - 6b)

Step-by-step explanation:

$\frac{-6}{ab} + \frac{a^{2} }{b^{2} }$

= $\frac{-6b + a^{3} }{ab^{2} }$

= $\frac{1}{ab^{2} }$ (a³ - 6b)

4 0

2 years ago

Which terms are like terms in the expression 5x + 9 + (-7x)

Veronika [31]

Answer:

5x and -7x

Step-by-step explanation:

they both end in the variable "x"

7 0

3 years ago

A college committee consists of 3 freshmen, 4 sophomores, 5 juniors, and 2 seniors. A subcommittee of 4 consisting of 1 person f

dezoksy [38]

Answer:

120

Step-by-step explanation:

The subcommittee needs to contain 1 out of 3 freshmen, 1 out of 4 sophomores, 1 out of 5 juniors and 1 out of 2 seniors. Assuming order is not important, the number of possibilities to pick the subcommittee members is given by:

$N=5*4*3*2=120$

There are 120 possible subcommittees.

5 0

3 years ago