Answer:
See below
Step-by-step explanation:
Since you didn't give an actual quadratic equation and just the standard form equation, I will reduce ax^2+bx+c=0:
(ax+p)(x+q) where p+q=b and pq=c
Step-by-step explanation:
1. The midpoint formula says the coordinates of the midpoint are the average of the endpoints.
x = (x₁ + x₂) / 2
y = (y₁ + y₂) / 2
I'll do #2 and #3 as examples.
2. x = (-4 + 10) / 2 = 3
y = (6 + -10) / 2 = -2
So the midpoint is (3, -2).
3. x = (-3 + -6.5) / 2 = -4.75
y = (-8 + -4.5) / 2 = -6.25
So the midpoint is (-4.75, -6.25).
Is it radius or circumference?
Answer:
whats the question?
Step-by-step explanation:
Answer:
it does have a solution x=0
Step-by-step explanation:
9x+15=3x+15
6x+15=15
6x=0
x=0
