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4 years ago

HELP WILL GIVE BRAINLIEST

Chemistry

1 answer:

zzz [600]4 years ago

5 0

Answer to this question should be C

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Water is formed when this happens

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3 years ago

I WILL GIVE BRAINLIEST PLEASE HELP ME I NEED HELP!

AleksAgata [21]

I think the answer would be trenches but I’m sorry if I’m wrong

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3 years ago

Help me I need to know how do do this or just give me answers lol

Pani-rosa [81]

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4 years ago

Salt in crude oil must be removed before the oil undergoes processing in a refinery. The

irina1246 [14]

Answer:

$\large \boxed{0.64 \, \%}$

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

$\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}$

2. Calculate the mass of salt in the salty oil

$\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}$

3. Calculate the mass of salt in the spent water

$\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}$

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g

5. Concentration of salt in washed oil

$\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}$

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3 years ago

Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3 What is the mass in grams of 17.16 mL of acetone?

Mashutka [201]

1 mL = 1 cm³

D = m / V

0.7857 = m / 17.16

m = 0.7857 x 17.16

m = 13.482 g

8 0

3 years ago