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skad [1K]
3 years ago
15

Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional.

Chemistry
2 answers:
lora16 [44]3 years ago
7 0
The 3 and 2 to the right of the components are subscriptions.

Setler [38]3 years ago
5 0

Explanation:

A balanced equation is an equation in which number of molecules on both left and right side are the same or equal.

When aluminium chloride decomposes then it gives aluminium and chlorine gas.

The decomposition reaction will be as follows.

        2AlCl_{3} (s) \rightarrow 2Al(s) + 3Cl_{2}(g)

Therefore, we can see that number of molecules on the reactant and product side are same. Hence, this equation is balanced.

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penetration probe

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it is a penetration probe

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6 0
3 years ago
Question 2Classify the following organic structures:CH3OCH3CH2CH2CHCH2CH3CH3NHCH3CH3CH(OH)CH₂CH3
Naily [24]

Within the options, we have four organic compounds. Let's see what the skeletal structure of the compounds is in order to identify them better:

The first compound CH3OCH3 has two methyl groups linked by a carbon atom, this type of compound is called an Ether

The second compound has a double bond, it is badly written but it seems that is an alkene.

The third compound has two methyl groups linked by nitrogen atoms, therefore will be an amine.

The last compound has a hydroxyl group, therefore it is an alcohol

Answer:

CH3OCH3 Ether

CH2CH2CHCH2CH3 Alkene

CH3NHCH3 Amine

CH3CH(OH)CH₂CH3 Alcohol

3 0
1 year ago
Mrs. Stark weighs 70kg. How much Potential Energy does she have if she stands on the roof of an 80m tall building?
8_murik_8 [283]
E = mgh

E = 70*9.81*80

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5 0
3 years ago
If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
USPshnik [31]

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = \frac{mass}{molar mass}  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = \frac{18.1}{143.2}   = 0.13moles

Number of moles of NH₃   = \frac{90.4}{17}   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

5 0
3 years ago
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