Answer:
penetration probe
Explanation:
it is a penetration probe
 
        
             
        
        
        
Within the options, we have four organic compounds. Let's see what the skeletal structure of the compounds is in order to identify them better:
The first compound CH3OCH3 has two methyl groups linked by a carbon atom, this type of compound is called an Ether
The second compound has a double bond, it is badly written but it seems that is an alkene.
The third compound has two methyl groups linked by nitrogen atoms, therefore will be an amine.
The last compound has a hydroxyl group, therefore it is an alcohol
Answer:
CH3OCH3 Ether
CH2CH2CHCH2CH3 Alkene
CH3NHCH3 Amine
CH3CH(OH)CH₂CH3 Alcohol
 
        
             
        
        
        
Answer:
3.64g
Explanation:
Given parameters: 
Mass of NH₃  = 18.1g 
Mass of Cu₂O  = 90.4g 
Unknown: 
Limiting reactant  = ? 
Mass of N₂ formed  = ? 
Solution: 
The reaction equation is given as: 
        Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O 
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species; 
   Number of moles =  
  
 Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol 
 Molar mass of NH₃  = 14 + 3(1) = 17g/mol 
Number of moles of Cu₂O =  = 0.13moles
   = 0.13moles 
Number of moles of NH₃   =  = 5.32moles
   = 5.32moles 
   From this reaction; 
        1 mole of  Cu₂O combines with 2 mole of NH₃
 So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃
                                               = 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess; 
 Mass of N₂; 
    Mass = number of moles x molar mass
     1 mole of Cu₂O  will produce 1 mole of N₂ 
     0.13 mole of Cu₂O  will produce 0.13 mole of N₂
     Mass  = 0.13 x (2 x 14) = 3.64g