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skad [1K]
3 years ago
15

Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional.

Chemistry
2 answers:
lora16 [44]3 years ago
7 0
The 3 and 2 to the right of the components are subscriptions.

Setler [38]3 years ago
5 0

Explanation:

A balanced equation is an equation in which number of molecules on both left and right side are the same or equal.

When aluminium chloride decomposes then it gives aluminium and chlorine gas.

The decomposition reaction will be as follows.

        2AlCl_{3} (s) \rightarrow 2Al(s) + 3Cl_{2}(g)

Therefore, we can see that number of molecules on the reactant and product side are same. Hence, this equation is balanced.

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Neve later believes that New Zealand's winter is caused by the sun circling to the other side
VARVARA [1.3K]

Explanation:

I need a help of math.

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3 0
2 years ago
A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete
topjm [15]

The given mass of cobalt chloride hydrate = 2.055 g

A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.

The mass of anhydrous cobalt chloride = 1.121 g anhydrate.

The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g

Converting mass of water of hydration present in the hydrate to moles using molar mass:

Mass of water = 0.934 g

Molar mass of water = 18.0 g/mol

Moles of water = 0.934 g * \frac{1 molH_{2}O }{18 g H_{2}O } =0.0519 mol H_{2}O

8 0
3 years ago
Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-1
jekas [21]

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

Explanation: pKa= -log(Ka)= 12.38. PH + pOH = 14.00

8 0
3 years ago
What is the % Yield if 3.8 g of Cu was produced?
seraphim [82]
83.9 is the answer i’m pretty sure
3 0
3 years ago
An excess of mg(s) is added to 100.ml of 0.400 m hcl. at 0c and 1 atm pressure, what volume of h 2 (g) can be obtained?
ra1l [238]
The balanced equation for the reaction between Mg and HCl is as follows
Mg + 2HCl --> MgCl₂ + H₂
stoichiometry of HCl to H₂ is 2:1

number of HCl moles reacted - 0.400 mol/L x 0.100 L = 0.04 mol of HCl
since Mg is in excess HCl is the limiting reactant 
number of H₂ moles formed - 0.04/2 = 0.02 mol of H₂

we can use ideal gas law equation to find the volume of H₂
PV = nRT 
where 
P - pressure - 1 atm x 101 325 Pa/atm = 101 325 Pa
V - volume
n - number of moles - 0.02 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 0 °C + 273 = 273 K
substituting these values in the equation 

101 325 Pa x V = 0.02 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K
V = 448 x 10⁻⁶ m³
V = 448 mL 
therefore answer is 
c. 448 mL 
5 0
3 years ago
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