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olganol [36]
2 years ago
14

What is the center of the atom called?

Chemistry
2 answers:
AnnZ [28]2 years ago
6 0

Answer:

nucleus

Explanation:

thats 100% the answer

GenaCL600 [577]2 years ago
3 0
The answer is nucleus
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What are covalent bonds
ValentinkaMS [17]

Answer:

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding

8 0
2 years ago
Is water wet? I give you a lot of points
UkoKoshka [18]

i mean technically, no. only because water is water and water makes things wet. you know? unless you pour water onto water then idk honestly, truly...

6 0
3 years ago
Read 2 more answers
Consider this chemical reaction. What chemical is reduced?<br> CH3OH + NAD --&gt; CH2O + NADH
nikklg [1K]

Answer:

CH3OH and NADH

Explanation:

The given chemical reaction is an redox reaction in which reduction and oxidation take place.

In the process of oxidation: electrons are loss while in the process of reduction: electrons are gained.

In the given redox reaction: CH3OH + NAD --> CH2O + NADH

NAD is reduced to NADH as NADH gains one hydrogen electron while CH3OH (methanol) is oxidized to CH2O (methanal)  by losing electrons.

So, CH3OH (methanol) and NADH are the reduced forms while NAD and CH2O (methanal) are oxidized forms.

5 0
3 years ago
In the Bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is _______________ the ene
yawa3891 [41]

Answer:

greater than

Explanation:

4 0
2 years ago
Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is
Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0
3 years ago
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