Answer:
a. 1.2 ohms
b. 6 ohms
Step-by-step explanation:
As with any problem involving evaluation of a formula, substitute the given values for the corresponding variables and do the arithmetic.
a.
![R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{2}+\dfrac{1}{3}}=\dfrac{1}{\left(\dfrac{5}{6}\right)}=\boxed{\dfrac{6}{5}=1.2}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7B1%7D%7B%5Cdfrac%7B1%7D%7BR_1%7D%2B%5Cdfrac%7B1%7D%7BR_2%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7B1%7D%7B3%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Cleft%28%5Cdfrac%7B5%7D%7B6%7D%5Cright%29%7D%3D%5Cboxed%7B%5Cdfrac%7B6%7D%7B5%7D%3D1.2%7D)
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b.
![R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{10}+\dfrac{1}{15}}=\dfrac{1}{\left(\dfrac{5}{30}\right)}=\dfrac{30}{5}=\boxed{6}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7B1%7D%7B%5Cdfrac%7B1%7D%7BR_1%7D%2B%5Cdfrac%7B1%7D%7BR_2%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Cdfrac%7B1%7D%7B10%7D%2B%5Cdfrac%7B1%7D%7B15%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Cleft%28%5Cdfrac%7B5%7D%7B30%7D%5Cright%29%7D%3D%5Cdfrac%7B30%7D%7B5%7D%3D%5Cboxed%7B6%7D)
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<em>Comment on these problems</em>
You will notice that the values in part (b) are 5 times those in part (a). So, it is no surprise that the answer in part (b) is 5 times the answer in part (a).
Answer:
Part A: yes
Part B: yes
Part C: yes
Step-by-step explanation:
Part A:
77² + 420² = 427²
5,929 + 176,400 = 182,329
182,329 = 182,329
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Part B:
279² + 440² = 521²
77,841 + 193,600 = 271,441
271,441 = 271,441
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Part C:
39² + 760² = 761²
1,521 + 577,600 = 579,121
579121 = 579,121
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3:40
1:13
it would be 13.3 repeated but since you round to the nearest dollar it would be 13. All I did was divide 40 by 3.
1/12 because you divide by 2