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olga55 [171]
3 years ago
12

The perimeter of the triangle is 4x+3y. Find the measure of the missing side.

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
What picture theres no pic
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Anyone know how to solve this??
Tom [10]

Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}

\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})

\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)

\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3

\implies x^k = x^3

\implies k = 3

7 0
3 years ago
Hey! Can someone do this real quick? 20 points!!!
likoan [24]

Answer:

i think about 80 cm or 100cm

5 0
3 years ago
Read 2 more answers
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
My name is Ann [436]

Answer: Choice C

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.

-----------------

In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.

Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.

8 0
3 years ago
4 to 8 = 15 to n Can someone show me the answer
melamori03 [73]

Answer:

n=30

Step-by-step explanation:

4         15

------ = --------

8           n

using cross products

4n = 8*15

4n = 120

divide by 4

4n/4 =120/4

n = 30

6 0
3 years ago
The rule that refers to grouping is blank property
baherus [9]

Answer:

associative property

Step-by-step explanation:

Grouping like this

a + (b + c) = (a + b) + c

or

a(bc) = (ab)c

is the associative property

5 0
2 years ago
Read 2 more answers
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