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V125BC [204]
2 years ago
7

Item 3

Mathematics
1 answer:
NikAS [45]2 years ago
5 0

Answer:

I'm taking the test right now so i'll tell you the right answer after I submit my test but for now I think it's C.

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Simplify. Assume that no denominator is equal to zero. (show work) <br> help please!!!!!
MrRa [10]

n^8

basically it's like this n^12/n^4 = n^(12-4) = n^8

5 0
3 years ago
Carson throws a ball upward into the air the height of the ball is determined by h(t)= -16t^2 +60t+ 5.5. what is the height in f
Alex777 [14]
The ball was initially thrown from a height of 5.5 feet and 5.5 is y intercept that it throm from 5.5 feet.
6 0
4 years ago
Multiple choice: 
Paha777 [63]
In the given you wrote -2, whereas it should be -2i

z = a + bi and in trigo form | z |.(cos Ф + i.sin Ф).
z = 0 -2i → | z |.(cos Ф + i.sin Ф)
Now let's calculate z:
 
z² = a²+b² → z² = 0² (-2.i)² → z = -2(i)² →z= -2(-1) → z = |2|
tan Ф = b/a = -2/0 → tan Ф → - ∞ ↔ Ф = -90° or Ф = 270°
 then the - 2 I ↔ |2|(cos 270° + i.sin 270°)

7 0
3 years ago
Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days
zvonat [6]

Answer:

  f)  a[n] = -(-2)^n +2^n

  g)  a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

  a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

  r^n -k²r^(n-2) = 0

  r^(n-2)(r² -k²) = 0

  r² -k² = 0

  r = ±k

  a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

__

f) k² = 4, so k = 2.

  a[0] = 0 = p + q

  a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

  2 = 2q

  q = 1

  p = -1

The solution is a[n] = -(-2)^n +2^n.

__

g) k² = 1/4, so k = 1/2.

  a[0] = 1 = p + q

  a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

  1/2 = q

  p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

 

5 0
3 years ago
Order of Operations with and without variables
lyudmila [28]
I think the answer is -4
6 0
3 years ago
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