Answer:
aerts is older by 1 year
Step-by-step explanation:
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
For both of the contests, the variable is the number of competitors which we can set as x.
Consequently, the equation should be 5.50x+34.60=4.25x+64.60
5.50x=4.25x+30
1.25x=30
x=24
The fee of the contests is the same when there are 24 competitors
Answer:
A and D
Step-by-step explanation:
All you need to do is locate the point (3,1) on the graph and figure out which two lines are intersecting it. In this case it is A and D so that is your solution.
Answer: The rocket will reach its max after 4 seconds
Step-by-step explanation:
Hi, to find the maximum height, we have to set the first derivative of the equation equal to zero.
y=-16x^2+128x+136
0 = (2)-16x +128
0= -32x+128
Solving for x:
32x = 128
x = 128/32
x = 4 seconds
The rocket will reach its max after 4 seconds
Feel free to ask for more if needed or if you did not understand something.
