Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given
There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:x
x^3+5x^2+16x-3
Step-by-step explanation:
Answer:
- Overall GPA=2.81
- It is not possible to get his GPA to 3.0 for graduation.
Step-by-step explanation:
The Student already has a GPA of 2.68 after 108 credit hours.
If he is taking 12 credit hours in his last semester and gets a perfect 4.0 GPA
Total Credits Earned Before = 2.68 X 108=2894.4
Projected Credit to be earned = 12 X 4= 48 Credits
Total credit Hour= 108+12=120 Hours
His Cumulative GPA = Total credits earned ÷ Total Credit Hour
Since 2.81 is less than 3.00, it is not possible to get his GPA to 3.0 for graduation.
well let's round. 90= 100, 75=80 that is how I face it. now 80 is 1/5 of 5/5= 100. so as a (%) we would sort it like:::: it is 80% out of +100 so he must have grown around 13%-16% due to him being 75kg in the past.
12????
i figured that out because i calculated the length and width which is 24, then I divided it by 2 because the radius is half of the middle so its 12? i dont know can someone help me too
