Can someone please help me with this i don't understand the way my teacher explained it
2 answers:
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Subsitution
y=3x+2
subsitute (3x+2) for y in other equation
2x+y=-4
2x+(3x+2)=-4
2x+3x+2=-4
5x+2=-4
minus 2 both sides
5x=-6
divide both sides by 5
subsitute back
(x,y)
the solution is
that is the first option
y=3x+2
subsitute (3x+2) for y in other equation
2x+y=-4
2x+(3x+2)=-4
2x+3x+2=-4
5x+2=-4
minus 2 both sides
5x=-6
divide both sides by 5
subsitute back
(x,y)
the solution is
that is the first option