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never [62]
3 years ago
8

Can someone please help me with this i don't understand the way my teacher explained it​

Mathematics
2 answers:
NISA [10]3 years ago
5 0

Answer:

I dont even understand that and im in 8th grade lol

bekas [8.4K]3 years ago
4 0

Answer:

7,476 would be your answer because

62,300 divided by 3% is 1,869

and 1,869 times 4 is 7,476

Step-by-step explanation:

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X−6>−2 solve the inequality
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Answer:

x>4

Step-by-step explanation:

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X^2+ 3x = 18 using zero product property
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Please help as I can’t figure this out :(
suter [353]

Both chords CE and FE subtend arcs of 110°. They are the same length: 24.

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3 years ago
It is known that the point P(-9,18) belongs to the graph of the function y=k/x. Find k.
riadik2000 [5.3K]

Answer:

k = (-162).

Step-by-step explanation:

A point of the form (x_{0},\, y_{0}) belongs to the graph of this function, y = k / x, if and only if the equation of this function holds after substituting in x = x_{0} and y = y_{0}.

The question states that the point (-9,\, 18) belongs to the graph of this function. Thus, the equation of this function, y = k / x, should hold after substituting in x = (-9) and y = 18:

y = k / x.

18 = k / (-9).

Solve this equation for the constant k:

\begin{aligned}k &= 18 \times (-9) \\ &= (-162)\end{aligned}.

Thus, k = (-162).

6 0
2 years ago
One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo
almond37 [142]

Answer:

(1) P(\bar X < 26 inches) = 0.0436

(2) P(27.5 inches < \bar X < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let \bar X = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

            Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean vertical  leap = 28 inches

            \sigma = standard deviation = 7 inches

            n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P(\bar X < 26 inches)

   P(\bar X < 26) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{26-28}{\frac{7}{\sqrt{36} } } ) = P(Z < -1.71) = 1 - P(Z \leq 1.71)

                                                 = 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < \bar X < 28.5 inches) = P(\bar X < 28.5 inches) - P(\bar X \leq 27.5 inches)

    P(\bar X < 28.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{28.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z < 0.36) = 0.64058 {using z table}                      

    P(\bar X \leq 27.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{27.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z \leq -0.36) = 1 - P(Z < 0.36)

                                                        = 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < \bar X < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0
3 years ago
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