9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
The answer is i beleve 75+15n
3/5 miles = 4 miles
1/5 miles = 4/3 miles
5/5 (1) mile = 20/3 miles = 6 2/3 miles
6 2/3 miles per hour
Answer:
D. 3
Step-by-step explanation:
To find the slope of a line, we can use the equation y2-y1/x2-x1=m or slope.
All we can do now is insert the values of the points into the equation.
-8-7/-4-1=m
-15/-5=m
3=m
Thus, the slope is 3.
Hope this helps!
Answer:
4096
Step-by-step explanation:
<em><u>Simplify:</u></em>
=((−4)3)2
=((−4)3)*((−4)3)
=((−4)*(−4)*(−4))*((−4)*(−4)*(−4))
=(−4)*(−4)*(−4)*(−4)*(−4)*(−4)
=(−4)6
<em><u>Step by Step:</u></em>
<u><em>((−4)3)2
</em></u>
<u><em>=(−64)2
</em></u>
<u><em>=4096</em></u>
<u><em /></u>
Answer: 4096
<em><u>Hope this helps.</u></em>
