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motikmotik
3 years ago
11

Pls help me macth the words with the defonitions\ math

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

Do what the 6th grader said

Step-by-step explanation:

Orlov [11]3 years ago
4 0

Answer:

Do what the 6th grader said

Step-by-step explanation:

They smart

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Please help with this pleaseee
saw5 [17]

Answer:

CED=126

Step-by-step explanation:

The total of all 3 angles should be 180

so:

180-38-16 (ABC is equal to ECD)

180-38-16=126

126=CED

5 0
2 years ago
Read 2 more answers
An asteroid is 10^{8} miles away from earth, and it is traveling at a speed of 10^{5} miles per day. How many days will it take
Nikolay [14]

Answer:

It will take 10^3 days for the comet to reach earth.

Step-by-step explanation:

10^8 = 100,000,000

10^5 = 100,000

100,000,000/100,000 = 1,000

1,000 is equal to 10^3

So it will take the comet 10^3 days to reach earth.

7 0
3 years ago
Billy is monitoring the exponential decay of a radioactive compound. He has a sample of the compound in a test tube in his lab.
Over [174]

Solution:

Formula for radioactive Decay is given by

R_{0}= R(1-\frac{S}{100})^t

R_{0}= Initial Population

R = Remaining population after time in hours

Rate of Decay = S % per hour

Initial Population = 72 grams

Final population = 15 grams

Rate of Decay = 35 % per hour

Substituting the values to get value of t in hours

72=15(1-\frac{35}{100})^t\\\\ 4.8= (0.65)^t\\\\ t= -3.64→→1 St expression

But taking positive value of t , that is after 3.64 hours the sample of 72 grams decays to 15 grams at the rate of 35 % per hour.

Now , it is also given that, Once the sample reaches a mass of 15 grams, Billy will continually add more of the compound to keep the sample size at a minimum of 15 grams.

Substituting these in Decay Formula

Final Sample = 15 gm

Starting Sample = 15 +k, where k is amount of sample added each time to keep the final sample to 15 grams.

Time is over 3.64 hours i.e new time = 3.64 + t

Rate will remain same i.e 35 % per hour.

15=(15+k)(1-\frac{35}{100})^{3.64+t}→→→  Final expression (Second) , that is inequalities can be used to determine the possible mass of the radioactive sample over time.







5 0
3 years ago
Read 2 more answers
Verify the identity. (cos x/ 1+ sin x) + (1+ sin x/cos x) = 2 sec x​
Gekata [30.6K]

Answer:

LHS

\frac{cos x}{1+ sin x} + \frac{1+ sin x}{cos x} \\=\frac{cos2(x)+1+2sin(x)+sin2(x)}{cos(x)(1+sin(x)} \\= \frac{2+2sin(x)}{cos(x)(1+sin(x))} \\\\=\frac{2 (1 + sin(x))}{cos(x)(1+sin(x))} \\= \frac{2}{cos (x)} \\= 2 sec x

= RHS PROVED

hope it helps :)

8 0
3 years ago
-26 times a number minus 22 is equal to 90 less than the number.
Novay_Z [31]

-26n -22= n - 90

-26 times a number: -26n

minus 22: -22

equal: =

90 less than a number: n - 90

Solving the Equation:

Move n to the left side of the equal sign (which becomes -n) in order to combine like terms:

-26n-n-22= -90

Move -22 to the right side of the equal sign which becomes +22

-26n-n=-90+22

solve both sides; -26n-n= -27n and -90+ 22= -78

-27n=-78

n= 2.888888

5 0
3 years ago
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