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Yuri [45]
3 years ago
11

Hye Lim drank 4/3 gallons of water in 11/2 hours. At this rate, how long will it take her to drink 4 gallons of water?

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

16.5 hours

Step-by-step explanation:

Here is the explanation. As Hye drinks 4/3 gallons of water in 11/2 hours, we have a constant rate. There are 12 thirds in 4, so we are trying to find how long it takes Hye to drink 12/3 gallon. In this case, 4/3x3=12/3, so we multiply 11/2 by 3 as well, which gives us 33/2 hours. 33/2 in decimal form is 16.5 hours. Hope it helps!

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m = 30b  where 'm' represents the amount of money and 'b' represents the number of boxes sold.

m is the dependent variable 
b is the independent variable
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What is the median of the data set: {24, 31, 12, 38, 12, 15}A)12B)19.5C)24D)23.5
QveST [7]

Answer: B: 19.5

Step-by-step explanation:

This data set is an even data set meaning that you're going to have to add and divide, so you put your data set in ascending order (highest # to lowest #) so 12,12,15,24,31,38 its an even data set so you're going to put them in groups (remember your finding the median, the middle numbers) so you have 12,12 (one group) and 31,38 (another group) (basically make it even!!) so now you're left with the middle numbers, you have to add them and then divide them by 2 so (15+24) ÷2 and you get your answer !!

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2 years ago
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3 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
4 years ago
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