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nexus9112 [7]
2 years ago
14

the product of five consecutive odd integers is 945 what is the greatest possible value of any of these integers

Mathematics
1 answer:
Troyanec [42]2 years ago
4 0
If 945 is the product of 5 CONSECUTIVE ODD  numbers, let's find the prime factors of 945:

945 = 5 x 7 x 27 , but we need 5 odd numbers:

945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1

945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9
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What is the solution to this system of equations?
Eduardwww [97]

Answer:

x = -2, y = 3

Step-by-step explanation:

Given equations are,

4x + 5y = 7 ---------(1)

3x - 2y = -12 ----------(2)

Multiply equation (1) by 3

12x + 15y = 21 ------(3)

Multiply equation (2) by (-4)

-12x + 8y = 48 --------(4)

Now add equations (3) and (4),

(12x + 15y) + (-12x + 8y) = 21 + 48

(12x - 12x) + (15y + 8y) = 69

23y = 69

y = 3

From equation (2),

3x - 2(3) = -12

3x - 6 = -12

3x = 6 - 12

x = -2

Therefore, x = -2 and y = 3 will be the answer.

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3 years ago
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vladimir2022 [97]
<h3>Answer: Choice B) 8.57</h3>

==================================================

Explanation:

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The corresponding sides pair up to form equal fractions. AB and DE form AB/DE which is equal to AC/DF, as these two sides correspond as well.

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x = 8.57142857142858

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3 years ago
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Answer:

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It's clear that the denominator is now a rational number, not an irrational one anymore.

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