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3 years ago

the product of five consecutive odd integers is 945 what is the greatest possible value of any of these integers

1 answer:

4 0

If 945 is the product of 5 CONSECUTIVE ODD numbers, let's find the prime factors of 945:

945 = 5 x 7 x 27 , but we need 5 odd numbers:

945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1

945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9

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Given right triangle ABC, what is the value of tan(A)?

Angelina_Jolie [31]

You didn't provide more information regarding triangle but from given options, it seems that triangle has ratio from shortest side to longest side would be 5 : 12 : 13

So 13 would be hypotenuse since it is longest.

Now A cannot be right angle because tangent is not defined at 90°.

Also tan(A) would be ratio of opponent side to adjacent side (think SOH CAH TOA)

So either opposite side would be 5 or 12, and adjacent side would be 12 or 5 respectively.

So the answer is either 5 / 12 or 12 / 5 but only option provided is 12/5 so that would be your answer.

Final answer: 12 / 5

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Sphinxa [80]

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Which equation represents a line which is perpendicular to the line y = 4/3x-6

SCORPION-xisa [38]

In order to be perpendicular, you must have a slope that is the opposite reciprocal, so the slope should by -3/4. So the equation could be y = -3/4x with any other number at the end.

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3 years ago

Write the explicit formula for the

Phoenix [80]

Answer:

$a_n=-10n+150$

Step-by-step explanation:

This is consider a linear pattern (arithmetic pattern).

We know this because it is either going up or down by the same number each time. It's going down by 10 in this case.

So -10 is the slope of this linear pattern.

The equation for a linear pattern is:

y=mx+b

where x represents the position the term is in

and

where y represents the actual term

and

where m is the slope

So we have y=-10x+b.

(x,y)

(term position in sequence, actual term)

(1,140)

(2,130)

(3,120)

(4,110)

We can find b by using a number with it's position in the sequence (that is plug in one of your points above).

y=-10x+b

140=-10(1)+b

140=-10+b

150=b (after adding 10 on both sides)

The explicit equation for the sequence is y=-10x+150.

They probably prefer you to write: $a_n=-10n+150$ instead.

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3 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

<u>Answer:</u>

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

<u>Solution:</u>

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

3 years ago