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nexus9112 [7]
3 years ago
14

the product of five consecutive odd integers is 945 what is the greatest possible value of any of these integers

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0
If 945 is the product of 5 CONSECUTIVE ODD  numbers, let's find the prime factors of 945:

945 = 5 x 7 x 27 , but we need 5 odd numbers:

945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1

945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9
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Which point is part of the solution of the inequality y 2 12x – 11.
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Point (0,0)

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Given the inequality y > 12x – 11.

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A) (1,0)

Substitute with x = 1 and y = 0

0 > 12*1 - 11

0 > 1   ⇒ Wrong

So, Point (1,0) is not part of the solution of the inequality.

B) (3,2)

Substitute with x = 3 and y = 2

2 > 12*3 - 11

0 > 25  ⇒ Wrong

So, Point (3,2) is not part of the solution of the inequality.

C) (1,1)

Substitute with x = 1 and y = 1

1 > 12*1 - 11

1 > 1   ⇒ Wrong

So, Point (1,1) is not part of the solution of the inequality.

D) (0,0)

Substitute with x = 1 and y = 0

0 > 12*0 - 11

0 > -11  ⇒ True

So, Point (0,0) is part of the solution of the inequality.

Also, see the attached figure which represents the given inequality

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