Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :
and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:
which solving for "t" becomes:
So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Answer:
The answer all together would be 5 minus n.
Step-by-step explanation:
a negative and a positive equals a positive so -1/2 + 1 1/2 would equal 2 and 2 + 3 equals 5. Then, the remaining numbers are 5 and n. The final answer is 5 minus n because n is unknown.
The formula to find the area of a sector = Ф*r²/2
Ф to be in radian, here Ф=45° =π/4
sector = 1/2(π/4)x 100
sector = 39.27 ≈39.3° (B)
Answer:
sin θ = 15/17
Step-by-step explanation:
First we have to know how much the hypotenuse measures.
to take out the hypotenuse we will use pitagoras, with the following formula.
h^2 = c1^2 + c2^2
c1 = 8
c2 = 15
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h = √ 289
h = 17
well to start we have to know the relationships between angles, legs and the hypotenuse.
a: adjacent
o: opposite
h: hypotenuse
sin θ = o/h
cos θ= a/h
tan θ = o/a
we want to know the sin of θ
sin θ = o/h
sin θ = 15/17
Answer:
y=-1/3x+1
Step-by-step explanation:
(picture explains)
