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3 years ago

Whats 4.288 to the nearest hundreth?

Mathematics

2 answers:

erastova [34]3 years ago

5 0

The answer would be 4.29

Savatey [412]3 years ago

3 0

4.29 I believe that is right

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is 1690.

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is 1690.

5 0

3 years ago

F(x) = 1/2 x - 5 What is f(6)?

Elodia [21]

Answer:

-2

Step-by-step explanation:

3 0

2 years ago

Find the length to the nearest centimeter of the diagonal of a square 30 cm. on a side

tiny-mole [99]

Answer:

42 cm.

Step-by-step explanation:

Please find the attachment.

Let x be the length of diagonal of the square.

We have been given that length of each side of a square is 30 cm. We are asked to find the length of the diagonal of square to the nearest centimeter.

We can see from our diagram that triangle AC is the diagonal of our square.

Since all the interior angles of a square are right angles or equal to 90 degrees, so we will use Pythagoras theorem to find the length of diagonal.

$AC^2=AD^2+DC^2$

Upon substituting our given values in above formula we will get,

$x^2=(30\text{ cm})^2+(30\text{ cm})^2$

$x^2=900\text{ cm}^2+900\text{ cm}^2$

$x^2=1800\text{ cm}^2$

Let us take square root of both sides of our equation.

$x=\sqrt{1800\text{ cm}^2}$

$x=42.4264\text{ cm}\approx 42\text{ cm}$

Therefore, the length of diagonal of our given square is 42 cm.

8 0

3 years ago

Quadrilateral HIJK has sides measuring 12 cm, 26 cm, 14 cm, and 30 cm. Which could be the side lengths of a dilation of HIJK wit

matrenka [14]

Answer:

Step-by-step explanation:

The quadrilateral HIJK has sides measuring 12 cm, 26 cm, 14 cm, and 30 cm.

When HIJK is dilated with a scale factor of 1.5, the side lengths becomes:

12 X 1.5 =18 cm

26 X 1.5 =39 cm

14 X 1.5 =21 cm

30 X 1.5 =45 cm

A dilation of HIJK with a scale factor of 1.5 will give us the side lengths:

18cm, 39cm, 21cm and 45cm.

The correct option is C.

6 0

3 years ago

ASAP!! PLEASE NEEDS TO BE ANSWERED TODAY

olganol [36]

Answer:

20.7 units

Step-by-step explanation:

The reading is:

-20.7

So, 20.7 units below the water's surface

8 0

2 years ago

Read 2 more answers