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aev [14]
3 years ago
13

What is the is point-slope (3,1) m=0?

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
The question is vague.
I will assume you're asking <span>What is the point-slope equation of a line which has a gradient of 0 and contains the point (3,1)?
</span>Since the gradient is 0, the line is horizontal or of the form 
y=c
Since from the point we can recognize that the value of y is 1, the resulting equation is 
<span>y=1</span>
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46 - 4 = 42

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F(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, ∞) and g(x) = 2x2 + 8x + 6,
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Answer:

B) Both functions have the same domain.

C) Both functions have the same x-intercepts.

D) Both functions are decreasing on the interval (−∞, −2).

Step-by-step explanation:

step 1

Find the vertex of f(x)

we know that

The x-coordinate of the vertex is the midpoint of the roots

we have

x=-1 and x=-3

so

the midpoint is

(-1-3)/2=-2

The y-coordinate of the vertex is -4 (because the range is [−4, ∞))

therefore

The vertex of f(x) is the point (-2,-4)

Is a vertical parabola open upward

The vertex is a minimum

The domain is all real numbers

step 2

we have

g(x)=2x^2+8x+6

Find the vertex

Factor the leading coefficient

g(x)=2(x^2+4x)+6

Complete the square

g(x)=2(x^2+4x+4)+6-8

g(x)=2(x^2+4x+4)-2

Rewrite as perfect squares

g(x)=2(x+2)^2-2

Is a vertical parabola open upward

The vertex is the point (-2,-2)

The domain is all real numbers

The range is the interval [−2, ∞)

Find the x-intercepts

For g(x)=0

0=2(x+2)^2-2

2(x+2)^2=2

(x+2)^2=1\\x+2=\pm1\\x=-2\pm1

so

The roots or x-intercepts are

x=-1 and x=-3

<u><em>Verify each statement</em></u>

A) Both functions have the same vertex

The statement is false

The vertex of f(x) is (-2,-4) and the vertex of g(x) is (-2,-2)

B) Both functions have the same domain.

The statement is true

The domain is all real numbers

C) Both functions have the same x-intercepts

The statement is true  (see the explanation)

D) Both functions are decreasing on the interval (−∞, −2)

The statement is true

Because the x-coordinate of the vertex is the same in both functions, and both functions open upward

7 0
3 years ago
Read 2 more answers
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