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aev [14]
3 years ago
13

What is the is point-slope (3,1) m=0?

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
The question is vague.
I will assume you're asking <span>What is the point-slope equation of a line which has a gradient of 0 and contains the point (3,1)?
</span>Since the gradient is 0, the line is horizontal or of the form 
y=c
Since from the point we can recognize that the value of y is 1, the resulting equation is 
<span>y=1</span>
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Answer:

1035272

Step-by-step explanation:

4 0
3 years ago
The product of 2 and a number increased by 7 is -36
Sholpan [36]
"The product" means you're multiplying the two numbers.
"a number" refers to a variable.
"increased" means you're adding.

2x + 7 = -36
3 0
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Sherman goes golfing every 6th day and Brad goes golfing every 7th day. If Sherman and Brad both went golfing today, how many da
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Read 2 more answers
The sum of three times the larger of two integers and twice the smaller is seven the difference between the two integers is four
Aloiza [94]

Answer:

x=3   y=-1

Step-by-step explanation:

3x+2y=7

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4 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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