By inspection, it's clear that the sequence must converge to
because
when
is arbitrarily large.
Now, for the limit as
to be equal to
is to say that for any
, there exists some
such that whenever
, it follows that
From this inequality, we get
As we're considering
, we can omit the first inequality.
We can then see that choosing
will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that
.
The worth of the car after it is paid off 5 years later given the rate of exponential depreciation is $32,842.34.
<h3>What is the worth of the car?</h3>
When the car declines in value, it means that the car is depreciating. The formula that can be used to determine the value of the car with the depreciationn rate is:
FV = P (1 - r)^n
- FV = Future value
- P = Present value
- R = rate of decline
- N = number of years
$42,000 x (1 - 0.048)^5 = $32,842.34
To learn more about future value, please check: brainly.com/question/18760477
The answer is 4:4 it takes 4 of each
Answer:
sin p -21/29
cos q 21/29 so here you go °~sohcahtoa~°
Step-by-step explanation:
sin means you find the soh part so you look for the oppisite over hyponuse
and for cos your looking for cah part so you find the adjsent over hypotnuse so the ansers is 21/29
Answer:
Simplify 2x - 4) + 7(x + 2).
9x + 6
9x - 4
09x - 6
= 9x+10
