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Harlamova29_29 [7]
3 years ago
7

Metal mercury at room temperature is a liquid. Its melting point is -39°C. The freezing point of alcohol is-114°C. How much warm

er is the melting point of mercury than the freezing point of alcohol?
Mathematics
1 answer:
Fofino [41]3 years ago
5 0
75 degrees warmer.

If you subtract -39 by -114, you get 75 which is the distance between the two temperatures
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So, find area of sector with radius 24 inches. And the find area of arc with r=14 inches.

Then subtract the area of sector with 14 inches  from area of sector with radius as 24 inches.

So, area of sector with r=24 in =\frac{135}{360} *\pi  *24^{2}

Simplify it,

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Simplify it

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Simplify it and use pi as 3.14.....

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