Angle ABC is an inscribed angle so would be half of the arc.
So, 4x-5.5=1/2(5x+25)
4x-5.5=5/2x+25/2
4x-5.5=2.5x+12.5
4x-2.5x=12.5+5.5
1.5x=18
x=12
So angle ABC=4(12)-5.5=48-5.5=42.5
Arc AC=5(12)+25=60+25=85
Check: 42.5(2)=85
Answer: Arc AC is 85
Answer:
2.33
Step-by-step explanation:
Answer:
A. Definition of angle bisector
Step-by-step explanation:
Given that ΔABC is an isosceles triangle where AB = BC, and that BD bisects ∠ABC, then by the definition of angle bisection of ∠ABC, we have;
m∠ABD = m∠CBD
The correct option is option A. Definition of angle bisector
<em>Also, given that ΔABC is an isosceles triangle and BD is the angle bisector of ∠ABC, we get;</em>
<em>AD = CD and BD = BD</em>
<em>We can therefore, also find that ΔABD ≅ ΔCBD by Side Side Side (SSS) rule of congruency</em>
First integral:
Use the rational exponent to represent roots. You have
![\displaystyle \int\sqrt[8]{x^9}\;dx = \int x^{\frac{9}{8}}\;dx](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%5Csqrt%5B8%5D%7Bx%5E9%7D%5C%3Bdx%20%3D%20%5Cint%20x%5E%7B%5Cfrac%7B9%7D%7B8%7D%7D%5C%3Bdx%20)
And from here you can use the rule

to derive
![\displaystyle \int\sqrt[8]{x^9}\;dx = \dfrac{x^{\frac{17}{8}}}{\frac{17}{8}}=\dfrac{8x^{\frac{17}{8}}}{17}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%5Csqrt%5B8%5D%7Bx%5E9%7D%5C%3Bdx%20%3D%20%5Cdfrac%7Bx%5E%7B%5Cfrac%7B17%7D%7B8%7D%7D%7D%7B%5Cfrac%7B17%7D%7B8%7D%7D%3D%5Cdfrac%7B8x%5E%7B%5Cfrac%7B17%7D%7B8%7D%7D%7D%7B17%7D%20)
Second integral:
Simply split the fraction:

So, the integral of the sum becomes the sum of three immediate integrals:



So, the answer is the sum of the three pieces:

Third integral:
Again, you can split the integral of the sum in the sum of the integrals. The antiderivative of the cosine is the sine, because
. So, you have

Answer:
For X and then determine Y. So when X is equal to negative 2. Notice that Y is going to be equal to negative 2 times negative 2 plus 5. Well negative 2 times negative 2 is 4 4 plus 5 equals 9.