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rusak2 [61]
3 years ago
11

Can someone Please Help me please please.

Mathematics
2 answers:
VikaD [51]3 years ago
5 0
X + 7 > 0 , x > -7
2x -5 > 0 , 2x > 5 , x > 2.5
since that if x is more than 2.5 ,it will be more than -7
so the correct answer is x > 2.5

klemol [59]3 years ago
3 0
Short Answer D
The point here is that the angle on the left (64o) produces a longer base line than the angle (35o) on the right. That means you need to set up your inequality to reflect that. It's a neat, but tricky question.

x + 7 > 2x - 5  Add 5 to both sides.
5 + 7 + x > 2x
12 + x > 2x    Subtract x from both sides.
12 > 2x - x
12 > x

The minimum distance is when the thirty five degree angle becomes 0. 
The distance cannot be less than 0, however.

2x - 5>0
2x > 5
x > 5/2
x > 2.5

So the correct answer to this is
2.5<x< 12

The answer is the 4th one down or D
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What is the measure of AC
Amiraneli [1.4K]
Angle ABC is an inscribed angle so would be half of the arc.
So, 4x-5.5=1/2(5x+25)
4x-5.5=5/2x+25/2
4x-5.5=2.5x+12.5
4x-2.5x=12.5+5.5
1.5x=18
x=12

So angle ABC=4(12)-5.5=48-5.5=42.5
Arc AC=5(12)+25=60+25=85

Check: 42.5(2)=85

Answer: Arc AC is 85
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2 years ago
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Tanya [424]

Answer:

2.33

Step-by-step explanation:

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1 year ago
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What is the reason for statement 3 in this proof?
const2013 [10]

Answer:

A. Definition of angle bisector

Step-by-step explanation:

Given that ΔABC is an isosceles triangle where AB = BC, and that BD bisects ∠ABC, then by the definition of angle bisection of ∠ABC, we have;

m∠ABD = m∠CBD

The correct option is option A. Definition of angle bisector

<em>Also, given that ΔABC is an isosceles triangle and BD is the angle bisector of ∠ABC, we get;</em>

<em>AD = CD and BD = BD</em>

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3 0
2 years ago
Please help with the questions in the image
algol13

First integral:

Use the rational exponent to represent roots. You have

\displaystyle \int\sqrt[8]{x^9}\;dx = \int x^{\frac{9}{8}}\;dx

And from here you can use the rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}+C

to derive

\displaystyle \int\sqrt[8]{x^9}\;dx = \dfrac{x^{\frac{17}{8}}}{\frac{17}{8}}=\dfrac{8x^{\frac{17}{8}}}{17}

Second integral:

Simply split the fraction:

\dfrac{3+\sqrt{x}+x}{x}=\dfrac{3}{x}+\dfrac{\sqrt{x}}{x}+\dfrac{x}{x}=\dfrac{3}{x}+\dfrac{1}{\sqrt{x}}+1

So, the integral of the sum becomes the sum of three immediate integrals:

\displaystyle \int \dfrac{3}{x}\;dx = 3\log(|x|)+C

\displaystyle \int \dfrac{1}{\sqrt{x}}\;dx = \int x^{-\frac{1}{2}}\;dx = 2\sqrt{x}+C

\displaystyle \int 1\;dx = x+C

So, the answer is the sum of the three pieces:

3\log(|x|) + 2\sqrt{x} + x+C

Third integral:

Again, you can split the integral of the sum in the sum of the integrals. The antiderivative of the cosine is the sine, because \sin'(x)=\cos(x). So, you have

\displaystyle \int \left( \cos(x)+\dfrac{1}{7}x\right)\;dx = \int \cos(x)\;dx + \dfrac{1}{7}\int x\;dx = \sin(x)+\frac{1}{14}x^2+C

7 0
3 years ago
How do you model function using rules tables and graphs?
Oksana_A [137]

Answer:

For X and then determine Y. So when X is equal to negative 2. Notice that Y is going to be equal to negative 2 times negative 2 plus 5. Well negative 2 times negative 2 is 4 4 plus 5 equals 9.

4 0
2 years ago
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