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marta [7]
2 years ago
5

HELP HAVING A BAD DAY

Mathematics
2 answers:
Brut [27]2 years ago
7 0

Answer:

40% of 250= 100ml

to get 40%, 100 -60

the answer is 100ml

SSSSS [86.1K]2 years ago
6 0

Answer:

I think he might need 100ml.

Step-by-step explanation:

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please guys help me please
MariettaO [177]

Answer:

C

Step-by-step explanation:

6 0
2 years ago
What equation models the data in the table if d = number of days and c = cost?
Anit [1.1K]
C = 22d is the correct answer because for every day the cost increases by 22 so two days mean the cost is equal to 22 (2)
4 0
3 years ago
Read 2 more answers
1. Calculate the simple interest over an amount of N$ 2500 that is invested for 3 years and 6 months at a rate of 7% pa.​
Umnica [9.8K]

Answer:

N$  612.5

Step by step explaination:

Given,

Principal or'P'=N$2500

Time or'n'=3 years & 6 months or 3.5 years

Rate of profit or 'r'=7% or 7/100

Profit or 'I'=?

_____________________________________

We know,

I=P*n*r

I=2500*3.5*7/100

I=612.5

So,simple interest is N$  612.5.

3 0
3 years ago
Find the Antilog of 547.840​
bija089 [108]

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

{ \boxed{ \bf{antilog \: of \: x =  \frac{x}{ log} =  {10}^{x}  }}}

Therefore:

{ \sf{anti(547.840) =  {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}

3 0
3 years ago
20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
1 year ago
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