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Svet_ta [14]
3 years ago
5

4) Given the line with equation 2x + 5y= 10 :

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0
A. <span>2x + 5y= 10
    5y= -2x+10
</span>-> y= -2/5x+2

b. The slope is 2

c. For the y  intecpet, x is always 0

y= -2/5x+2
y= -2/5(0)+2
y=0+2
y=2

(0,2) is the y-interecpt

d. Please veiw below

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Suppose that 16% of people have a dog. 32% of people have a cat, and 10% of people own both. What is the probability that someon
Julli [10]

Answer:

0.38

Step-by-step explanation:

Let the even that a person has a dog be A. The probability is given 16% this implies:

<em>P(A)</em> = 0.16 ..... (1)

Let the event that a person has a cat denote by B. The probability of B is given to be 32% this implies....  

<em>P(B</em>) = 0.32 ..... (2)

Then the event that a person has a dog and a cat will be denoted by A∩B. The probability of A∩B is given to be 10%: This implies:

<em>P(A∩B= = 0.12 .......(3)</em>

The event that someone owns a cat and a dog will denoted by the event <em>A∪B.</em> It is observed that A and B are not disjoint. This implies that the probability of this event is depicted as:

<em>P(A∪B) = P (A) + P(B) - P(A∩B)</em>

Substitute (1) , (2) and (3), in the above, we get:

<em>P(A∪B) = 0.16 + 0.32 - 0.10 = 0.38</em>

7 0
3 years ago
textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year old
Butoxors [25]

Testing the hypothesis, we have that:

a)

The null hypothesis is: H_0: \mu = 128

The alternative hypothesis is: H_1: \mu \neq 128

b) The p-value of the test is of 0.1212.

c) Since the <u>p-value of the test is of 0.1212 > 0.05</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

d) Since <u>|z| = 1.55 < 1.96</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item a:

At the null hypothesis, we <u>test if the mean is the same</u>, that is, of 128 texts every day, hence:

H_0: \mu = 128

At the alternative hypothesis, we <u>test if the mean is different</u>, that is, different of 128 texts every day, hence:

H_1: \mu \neq 128

Item b:

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

The parameters are:

\overline{x} is the sample mean.

\mu is the value tested at the null hypothesis.

\sigma is the standard deviation of the population.

n is the sample size.

For this problem, the values of the parameters are: \overline{x} = 118.6, \mu = 128, \sigma = 33.17, n = 30

Hence, the value of the test statistic is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{118.6 - 128}{\frac{33.17}{\sqrt{30}}}

z = -1.55

Since we have a two-tailed test, as we are testing if the mean is different of a value, the p-value is P(|z| < 1.55), which is 2 multiplied by the p-value of z = -1.55.

Looking at the z-table, z = -1.55 has a p-value of 0.0606

2(0.0606) = 0.1212

The p-value of the test is of 0.1212.

Item c:

Since the <u>p-value of the test is of 0.1212 > 0.05</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item d:

Using a z-distribution calculator, the critical value for a <u>two-tailed test</u> with <u>95% confidence level</u> is |z| = 1.96.

Since <u>|z| = 1.55 < 1.96</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

A similar problem is given at brainly.com/question/25369247

4 0
3 years ago
a cinder block is sitting on a platform 20 high. lt weighs 79n. The block has_____ energy. calculate it.
Leni [432]
A cinder block is sitting on a platform 20 m high. It weighs 79 N. The block has Gravitational Potential Energy.

Calculations:
Ep = mgh = mg = Fg
Ep = (Fg)(h)
Ep = (79N)(20 m)
Ep = 1580 J.

I believe the block's potential energy with respect to gravity is 1580 J.
3 0
3 years ago
Bab needs help please!
ASHA 777 [7]

Answer:

282.6 in³

Step-by-step explanation:

Volume = area circle * height

Area circle = πr²

Area circle = 3.14 * 9 = 28.26

28.26 * 10 = 282.6 in³

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
Read 2 more answers
Let's simplify.<br>(a)<br>5x 3x<br>+<br>2a 4a​
Alchen [17]

Step-by-step explanation: hopefully this helps

3 0
3 years ago
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