Question

I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the

Answer 1

Hello!

I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the  balloon with me to Denver, where the air pressure is 0.85 atm, what will  the new volume of the balloon be?

• We have the following data:

V1 (initial volume) = 15 L

P1 (initial pressure) = 1.0 atm

P2 (final pressure) = 0.85 atm

V2 (final volume) = ? (in ml)

• We have an isothermal transformation, its temperature remains constant, the volume and pressure of the gas are inversely proportional, that is, if the gas pressure in the container increases, so its volume decreases. Applying the data to the formula of Boyle's Law, we have:

$P_1*V_1 = P_2*V_2$

$1.0*15 = 0.85*V_2$

$15 = 0.85\:V_2$

$0.85\:V_2 = 15$

$V_2 = \dfrac{15}{0.85}$

$V_2 = 17.647... \to \boxed{\boxed{V_2 \approx 17.65\:L}}\:\:\:\:\:\:\bf\purple{\checkmark}$

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Answer 2

Answer:

17.65 L

Explanation:

- Use Boyle's Law

- Rearrange formula (V2 = V1P1/P2)

- Put in the values and solve

- Hope this helped! Let me know if you need a further explanation.