-2.5089 kJ is the amount of heat is released by the combustion of the naphthalene.
<h3>How we calculate the released heat?</h3>
Released amount of heat is calculated by using the below formula:
Q = -mcΔT, where
m = mass of naphthalene = 0.25g
c = specific heat of calorimeter = 4.13 kJ/°C
ΔT = change in temperature = 26.43°C - 24°C = 2.43°C
Putting all these values in the above equation, we get
Q = - (0.25 × 4.13 × 2.43) = - 2.5089 kJ
Hence, - 2.5089 kJ heat is released.
To know more about released heat, visit the below link:
brainly.com/question/13439286
The student needs to dilute the stock to get the proper concentration. And during the dilution, the molar number of solute will not change. So the volume of stock needed is 2*0.1/1.75=0.114 L. Then dilute to 2.00 L.
Answer:
Frequency of photon is 0.513×10¹⁵ s⁻¹
Explanation:
Given data:
Energy of photon = 3.4×10⁻¹⁹ J
Frequency of photon = ?
Planck's constant = 6.63 × 10⁻³⁴ Js
Solution:
Formula:
E = hf
3.4×10⁻¹⁹ J = 6.626 × 10⁻³⁴ Js × f
f = 3.4×10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js
F = 0.513×10¹⁵ s⁻¹
Frequency of photon is 0.513×10¹⁵ s⁻¹.
<span>d. flourine </span> fluorine<span> is the most reactive halogen
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