The compound (A) is 2-bromo-pentane. See attached picture for the chemical diagram.
Explanation:
2-bromo-pentane (A) reacts with bromine (Br₂) under UV light to form 2,2-dibromopentane and HBr. Also 2-bromo-pentane (A) reacts with NaSH to from pentane-2-thiol, which have an asimetric carbon, and NaBr.
You may find the chemical reactions and diagrams of the compounds in the attached picture.
Learn more about:
structure of organic compounds
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Answer:
The cathode is the electrode where the reduction takes place.
Explanation:
Cell has three components:
an electrolyte and two electrodes which is a cathode and an anode.
Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.
<u>In electrolytic cell:</u>
Negatively charged electrode is the cathode where the process of reduction takes place.
Positively charged electrode is the anode where the process of oxidation takes place.
<u>In galvanic cell:</u>
Positively charged electrode is the cathode where the process of reduction takes place.
Negatively charged electrode is the anode where the process of oxidation takes place.
<u>So, the correct answer is - The cathode is the electrode where the reduction takes place.</u>
<h3>
Answer:</h3>
The centripetal acceleration is 26.38 m/s²
<h3>
Explanation:</h3>
We are given;
- Mass of rubber stopper = 13 g
- Length of the string(radius) = 0.93 m
- Time for one revolution = 1.18 seconds
We are required to calculate the centripetal acceleration.
To get the centripetal acceleration is given by the formula;
Centripetal acc = V²/r
Where, V is the velocity and r is the radius.
Since time for 1 revolution is 1.18 seconds,
Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)
Therefore;
Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec
= 4.953 m/s
Thus;
Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m
= 26.38 m/s²
Hence, the centripetal acceleration is 26.38 m/s²
Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V =
n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm ·
12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.
