Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.
Explanation:
Answer:
The correct answer is the IONIC bond.
Explanation:
Answer:
<h3><em><u>Magnesium has an atomic number of 12, which means its neutral atom has 12 electrons. The Mg2+ ion is formed when the neutral magnesium atom loses 2 electrons, which brings its total number of electrons to 10</u></em></h3>
(a) The magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
Explanation:
The force acting between two charged particles separated by a distance is termed as Coloumb's force or electrostatic force. It can be termed as electrostatic force of attraction if the the force acting between the charges are oppositely charged. And it can be termed as electrostatic force of repulsion if the charges are similar or like charges.
In the present case, there is a positive and negative charge, so electrostatic force of attraction will be acting between them. As per Coloumb's law, the electrostatic force of attraction is directly proportional to the product of charges and inversely proportional to the square of distance of separation.

Here, k is the constant of proportionality which is equal to 9 ×
and Q, q are the two charges, d is the distance of separation.
So here Q = 5.5 ×
and q = - 3.5 ×
and d = 0.28 m
Then, 
So the magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
Answer:
Angular frequency is 20 rad/s.
Explanation:
Given that,
A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :
.....(1)
The general equation of oscillating particle is given by :
.......(2)
Compare equation (1) and (2) we get :

So, the angular frequency of the oscillation is 20 rad/s.