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12345 [234]
2 years ago
11

block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequen

cy ( ω ω ) of oscillation? x ( t ) = 1.5 cos ( 20 t ) x(t)=1.5cos⁡(20t)
Physics
1 answer:
faltersainse [42]2 years ago
7 0

Answer:

Angular frequency is 20 rad/s.      

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

x(t)=1.5\cos(20\ t).....(1)

The general equation of oscillating particle is given by :

x(t)=A\cos(\omega t).......(2)

Compare equation (1) and (2) we get :

\omega=20\ rad/s

So, the angular frequency of the oscillation is 20 rad/s.

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The drawings show three examples of the force with which someone pushes against a vertical wall. In each case the magnitude of t
Monica [59]

Complete Question

The complete question is shown on the

Answer:

The ascending order would be 2nd < 1st < 3rd

Explanation:

Generally the the Normal force is mathematically represented as

                      Normal \ Force  = Fsin \theta

=>                    Normal \ Force \  \alpha  \  sin \theta

For the first drawing  the value   \theta is between that of the the second and the third drawing so the Normal force would also be between the normal forces of the second and the third drawing

For the second drawing whose value of \theta is less than that of the first and the third the normal force would also be less than that of the first and third

For the the third drawing whose value is (90°) which is higher than the first and the second the normal force would also be higher than the first and the second

         

4 0
2 years ago
Read 2 more answers
Momentum is a measure of the<br> of an object.<br> Which term accurately completes the sentence?
RideAnS [48]

Answer:

Momentum is define as the product of the mass and velocity of a body. It is measured in Kgm/s.

Explanation:

Momentum is the product of mass and velocity of an object. When an object or a body of mass 'm' is moving with velocity 'v', then its momentum can be determined as;

momentum (P) = mass × velocity

i.e            P = m × v

                  = mv

It is measured in Kgm/s.

The change in momentum of a body is referred to as its impulse (Ft).

ΔP = m(v - u) = Ft

Where: P is the momentum of the object, m is its mass, v is its final velocity, u is the initial velocity, F is the force and t is the time in which the force acts.

8 0
3 years ago
Read 2 more answers
Suppose you have a Frisbee with a mass of 0.10 kg. You first throw it with a force of 5N and then change the force you throw it
natali 33 [55]

Answer:

The acceleration increases.

Explanation:

From Newton's 2nd Law, we have \Sigma F=ma. We can see that force is directly proportional to mass and acceleration. Therefore, as force increases, either mass or acceleration must increase as well, and vice versa. Since mass is maintained here, if you increase the force applied to the Frisbee, the acceleration will increase as well.

8 0
3 years ago
(1) find the density of a substance if the mass of the substance is 150kg and dimension 20mby10mby5m
Vikentia [17]

Answer:

0.15kg/m³

Explanation:

Density = mass/ volume

Given that

Mass = 150kg

Note that volume = length x breadth x height

Volume = 20 x 10 x 5

Volume = 1000m³

Density = mass ➗ volume

Density = 150kg ➗ 1000m³

Density = 0.15kg/m³

I hope this was helpful, Please mark as brainliest  

3 0
3 years ago
un conductor de plata (p=1,6x10°-6ohm x m) tiene una seccion de 5x10°-6 m°2 y una longitud de 110 m . calcular la resistencia
Alexus [3.1K]

Responder:

35,2 ohm.

Explicación:

Dado:

La resistencia específica del conductor es,

La longitud del conductor es,

El área de la sección transversal del conductor es,

Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

Por lo tanto, la resistencia se puede expresar como:

R=\frac{\rho\times l}{A}

Ahora, conecte los valores dados y resuelva para 'R'. Esto da,

R=\frac{1.6\times 10^{-6}\ ohm\cdot m\times 110\ m}{5\times 10^{-6}\ m^2}\\\\R=35.2\ ohm

Por lo tanto, la resistencia del conductor es de 35,2 ohm.

4 0
3 years ago
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