Question

block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequency ( ω ω ) of oscillation? x ( t ) = 1.5 cos ( 20 t ) x(t)=1.5cos⁡(20t)

Answer 1

Answer:

Angular frequency is 20 rad/s.      

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

$x(t)=1.5\cos(20\ t)$.....(1)

The general equation of oscillating particle is given by :

$x(t)=A\cos(\omega t)$.......(2)

Compare equation (1) and (2) we get :

$\omega=20\ rad/s$

So, the angular frequency of the oscillation is 20 rad/s.