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Mashutka [201]
3 years ago
12

Can a physical change, change what a substance is

Physics
1 answer:
Elden [556K]3 years ago
7 0
No the substance will remain the same substance as before.
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According to Galileo, this quantity is not needed to keep a body in motion under ideal conditions.
Sergio [31]
This condition is called Galileo's Law of Inertia which states that all bodies accelerate at the smart rate , no matter what are their masses or size. Inertia is that tendency of matter to resist changes in its velocity.  <span>Isaac Newton's first law of motion captures the concept of inertia. </span>
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3 years ago
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Whats the answer? Will give brainliest
kupik [55]

Answer:

The answer to your question is:  letter D

Explanation:

Fussion is combine light nuclei to form heavy nuclei

a)  This is wrong the definition says, combine light nuclei to form hevier nulcei

b)  Both fussion and fission are about radioactive compounds

c) Both fussion and fission use radioactive reactants

d) Yes, this is a characteristic of fussion

6 0
4 years ago
1) Construct a graph showing the relationship between and independent variable and a dependent variable. 2) Demonstrate potentia
lana66690 [7]

Answer:

lolfsedddddddddddddd

Explanation:

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4 years ago
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A 5.00 kg pendulum swings back and forth. At the top of its arc, it reaches a height of 0.36 m. What is the velocity of the pend
ella [17]
Tools we'll use:

--     Gravitational potential energy = (mass) x (gravity) x (height)

--     Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing,
its potential energy is

                             (mass) x (gravity) x (height)

                         =  (5 kg) x (9.8 m/s²) x (0.36 m)

                         =      (5 x 9.8 x 0.36)        joules

                         =            17.64 joules .

Energy is conserved ... it doesn't appear or disappear ...
so that number is exactly the kinetic energy the pendulum
has at the bottom of the swing, only now, it's kinetic energy:

                   17.64 joules  =  (1/2) x (mass) x (speed)²

                   17.64 joules  =  (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

                   17.64 joules / 2.5 kg  =  speed²

Write out the units of joules:

                   17.64 kg-m²/s²  /  2.5 kg  =  speed²

                   (17.64 / 2.5) (m²/s²)  =  speed²

                       7.056 m²/s²  =  speed²

Take the square root
of each side:              Speed = √(7.056 m²/s²)

                                           =    2.656 m/s .

Looking through the choices, we're overjoyed to see
that one if them is  ' 2.7 m/s '.  Surely that's IT !
_______________________________

Note:
The question asked for the pendulum's 'velocity', but our (my) calculation
only yielded the speed.

In order to describe a velocity, the direction of the motion must be known,
and the question doesn't give any information on exactly how the pendulum
is hanging, and how it's swinging. 

We know that at the bottom of its swing, the motion is completely horizontal,
but we have no clue as to what direction.  So all we can discuss is its speed.
6 0
3 years ago
how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at
DiKsa [7]

Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

\vec F_n=m\vec a

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

\vec F_1=

\vec F_1=\ N

The components of the second force are

\vec F_2=

\vec F_2=\ N

The net force is

\vec F_n=

\vec F_n=\ N

The magnitude of the net force is

|F_n|=\sqrt{14.64^2+54.64^2}

|F_n|=\sqrt{3200}=56.57\ N

The acceleration has a magnitude of

\displaystyle |a|=\frac{|F_n|}{m}

\displaystyle |a|=\frac{56.57}{20}

|a|=2.83\ m/s^2

The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

\theta=75^o

5 0
3 years ago
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