The equation to be used is written as:
ρ = nA/VcNₐ
where
ρ is the density
n is the number of atoms in unit cell (for FCC, n=4)
A is the atomic weight
Vc is the volume of the cubic cell which is equal to a³, such that a is the side length (for FCC, a = 4r/√2, where r is the radis)\
Nₐ is Avogradro's constant equal to 6.022×10²³ atoms/mol
r = 0.1387 nm*(10⁻⁹ m/nm)*(100 cm/1m) = 1.387×10⁻⁸ cm
a = 4(1.387×10⁻⁸ cm)/√2 = 3.923×10⁻⁸ cm
V = a³ = (3.923×10⁻⁸ cm)³ = 6.0376×10⁻²³ cm³
ρ = [(4 atoms)(195.08 g/mol)]/[(6.0376×10⁻²³ cm³)(6.022×10²³ atoms/mol)]
ρ = 21.46 g/cm³
Answer:
28.2 kg
Explanation:
Data provided in the question:
Mass of dog, m = 9.4 kg
Velocity of the dog with respect to water, v = 0.48 m/s
Velocity of the canoe, V = - 0.16 m/s [ - sign means velocity in opposite direction]
Now,
Let the mass of canoe be 'M'
Therefore,
From the conservation of momentum, we have
⇒ mv + MV = 0
or
⇒ 9.4 × 0.48 + M(- 0.16) = 0
or
⇒ 4.512 - 0.16M = 0
or
⇒ 0.16M = 4.512
or
⇒ M = 28.2 kg
Answer:
Incomplete question
Complete question:
a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 44kg , the acceleration of the object is 4m/s². If the same force acts upon another object whose mass is 11kg what is this object's acceleration?
Answer: 8m/s²
Explanation:
From the statement we deduced that acceleration varies inversely with mass where force was kept constant.
Therefore,
F/m = a or F = ma
For the first statement, substituting the mass and acceleration gives:
F = 44 x 4 = 88N
Applying the force above to the second mass gives us:
a = 88/11 = 8m/s²
Solid phase. The atoms are tightly packed and vibrate.
