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Delvig [45]
3 years ago
9

At 57 degrees fahrenheit, a certain insect chirps at a rate of 100 times per minute, and at 65 degrees, they chirp 156 times per

minute. Write an equation in slope-intercept form that represents the situation.
Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

57= 100   65=156-8=158

Step-by-step explanation:

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Each letter of the word "rainbow" has been written on a separate slip of paper and put into a box. Find the probability of selec
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Hshshshajhehwjqjwjehe
3 0
3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
The old city park is rectangular. It has a length of 350 meters. It has a width of 125 meters. What is the perimeter, in meters,
Natali5045456 [20]

(350x2=700) + (125x2=250) 700+250=950 so the perimeter is 950 meters long I hope this helps!

5 0
3 years ago
find the elasped time from 10:11 to 5:34 pls show your work . A) 5hrs and 37mins , B) 4hrs , C) 5h 23mins , D) 4hr 37mins
Bingel [31]
The question as you wrote it doesn't fit the answers. However, one of the answers fits if you meant
"elapsed time from 5:34 to 10:11".

There are many ways to do this. Try first taking the time from 5:34 to 6:11, and after that finding the time from 6:11 to to 10:11.

In a way, 6:00 is the same thing as 5:60. Add 11 to that and you can see that 6:11 is the same as 5:71. Now that you have an easy way to find the time from 5:34 to 6:11.
6:11 - 5:34 isn't easy.
But 5:71 - 5:34 is quite easy. 71 - 34 is 37.

So, from 5:34 to 6:11 there are 37 minutes.

Now the easy part, finding the time from 6:11 to 10:11. Since the minutes are the same, just subtract the hours. 10 - 6 = 4 hours.

Now you have the hours and minutes, which number 4 hours and 37 minutes.
8 0
3 years ago
log8x=2 solve for x by converting the logarithm to an exponential equation. (i already know the answer is 12.5 but i need the wr
swat32

Answer:

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Step-by-step explanation:

3 0
3 years ago
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