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3 years ago

Simplify the rational expressions. State any excluded values. X^2-4/2-x

Mathematics

1 answer:

tatiyna3 years ago

4 0

Answer:

-x-2; x $\neq$ 2

Step-by-step explanation:

$\frac{x^2-4}{2-x}$ -->

$\frac{(x-2)(x+2)}{(2-x)}$ -->

-(x+2); x CAN'T equal 2, because the denominator of the original fraction would be 0, which would make the term undefined.

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Solve the equation for Y<br> 3y=-6x+1

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Please answer me question 3 solving part

Illusion [34]

Answer:

1. D

2. B

3. A

Step-by-step explanation:

Question 1:

The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.

Question 2:

Given that <KLM = x°

<KML = 50°

<JKL = (2x - 15)°

According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.

2x - 15 = x + 50

Solve for x

2x - x = 15 + 50

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Therefore, <KLM = 65°

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<JKL = 2x - 15

Plug in the value of x

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3 years ago

Which points are on the graph of the equation - 3x + 6y + 5 = -7?

ludmilkaskok [199]

Answer:

C and E

Step-by-step explanation:

To solve this problem, let's plug in each coordinates into the equation.

$-3(-3) + 6(6) + 5 = -7$
$9 + 36 + 5 = -7$
$50 = -7$
$50 \neq -7$
A. cannot be the answer, as 50 does not equal -7.

$-3(-2) + 6(0)+5=-7$
$6+0+5=-7$
$11=-7$
$11\neq -7$
B. cannot be the answer, as 11 does not equal -7.

$-3(0) + 6(-2) + 5 = -7$
$0 - 12 + 5 = -7$
$-12 + 5 = -7$
$-7 = -7$
C. can be the answer, as -7 does equal -7.

$-3(6)+6(-3)+5=-7$
$-18-18+5=-7$
$-36+5=-7$
$-31\neq -7$
D. cannot be the answer, as -31 does not equal -7.

$-3(8) + 6(2) + 5 = -7$
$-24 + 12 + 5 = -7$
$-12 + 5 = -7$
$-7 = -7$
E. can be the answer, as -7 does equal -7.

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2 years ago