The nth term of a sequence is given by 2n+1.<br>Write down the first four terms of the sequence.

The x-intercepts of f(x) = sin (x + π/4) are ______

vladimir1956 [14]

On the interval [-2π,2π], the x intercepts are:
-5π/4, -π/4, 3π/4, 7π/4

3 0

3 years ago

Solve the equation for all real solutions.<br> 15r2 – 6r – 3 = -2r

Solnce55 [7]

Answer:

Step-by-step explanation:

hello :

15r² – 6r – 3 = -2r

15r² – 6r – 3 +2r =0

15r²-4r -3 =0

delta =b² -4ac a=15 b=-4 c=-3

delta =(-4)² - 4(15)(-3)=196 = 14²

r1 = (-b - √delta ) /2a = (4-14)/30 = -10/30 = -2/6 = -1/3

r2 = (-b + √delta ) /2a = (4+14)/30 = 18/30 = 3/5

4 0

3 years ago

Find the complex cube roots of 8(cos(4pi/5)+isin(4pi/5))

exis [7]

Answer:

-6.47+4.70i.

Brainliest

Step-by-step explanation:

100% sure

7 0

4 years ago

Kiara downloaded 264 pictures from her cell phone to her computer. These pictures took up 528 megabytes of space on her computer

Anettt [7]

Answer: 70

Step-by-step explanation: 528/264 * 35 = 70

6 0

4 years ago

Read 2 more answers

Match the function in the left column with its period in the right column.

kiruha [24]

The results for the matching between function and its period are:

Option 1 - Letter D
Option 2 - Letter A
Option 3 - Letter C
Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

$\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}$

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}$

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi$

Thus, the option 1 matches with the letter D.

2) Option 2

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}$

Thus, the option 2 matches with the letter A.

3) Option 3

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi$

Thus, the option 3 matches with the letter C.

4) Option 4

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}$

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0

2 years ago

The nth term of a sequence is given by 2n+1.Write down the first four terms of the sequence.​

The nth term of a sequence is given by 2n+1.Write down the first four terms of the sequence.