The perimeter of a rectangle is 18 meters. If the length of the rectangle is 6 meters what is the width(in meters)?

Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2 and 5 tenths over 5 and 59 hundredths.

Maru [420]

Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;

Hence:

AC = 2 x XY
CB = 2 x YZ

<h3>What is the triangle about?</h3>

From the question given; Triangle XYZ is known to have been dilated by a scale factor of 2 to form a type of triangle known as triangle ACB, So therefore, XYZ and ACB are known to be the same or similar triangles.

Since Angles Y and C are known to both measure 90 degrees, and angles A and X are said to be congruent. Therefore:

tanX = tanA = 5 over 2 and 5 tenths

AC = 2 x XY

CB = 2 x YZ

For part B:

cosX=Base/Hypotenuse

cos A=AC/AB

AC = 2.05

AB = 5.59

Therefore, Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;

Hence:

AC = 2 x XY
CB = 2 x YZ

Learn more about triangles from

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5 0

2 years ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

Solve the quadratic equation: 3x^2+x-5=0

adell [148]

3x²+x-5=0

a = 3, b = 1, c= -5

-> ∆ ( delta ) = b²-4ac = 61 > 0

-> x1 =( -b+√∆ )÷ 2a =...

x2 = (-b-√∆)÷2a =...

p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.

4 0

2 years ago

Help pleasee and thanks

Assoli18 [71]

Answer if D hope it helps!

3 0

3 years ago

Perpendicular lines intersect to form four right angles. never always sometimes

natima [27]

Answer:

Always

Step-by-step explanation:

The definition of a perpendicular line is that it intersects another at a 90 degree angle. Using this, by verticals, the opposite corner angle must also be 90-degrees, and since one side of a line is 180 degrees, 180-90 = 90, which ensure the rest of the angles will be 90 degrees too.

3 0

3 years ago

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