Answer:
75% of $20 is $15
Step-by-step explanation:
Hope this helps
Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
4
−
4
+
8
2
+
8
Step-by-step explanation:
Answer:
0 solutions / no solutions
Step-by-step explanation:
If two lines have the same slope but different y-intercepts, it means that they are parallel.
For example, we have two lines:
y = x
y = x + 1
Both lines have the same slope of 1, but different y - intercepts. Because each equation increases the x and y at the same right (slope) but started at different points, the two equations will never touch.
It's similar to two runner who run at the same pace. If one runner started 50 meters ahead, that runner will always be ahead 50 meters (y-intercept) because they both run at the same rate.
