Consider the absolute value equation x+2=3

1 answer:

3 0

X would equal 1 in this problem since 1+2=3 and the absolute value(s) in this equation would be -1+(-2)=3 since, a negative plus a negative equals a positive.

I hope this helped you!

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Expand the following using either the Binomial Theorem or Pascal’s Triangle.<br> (x - 5)5

NemiM [27]

Pakal triangle is hard to do with long things, but it is easy up to like 5 degree
we look at the row for 5th degree (6th row)
the sequence is
1,5,10,10,5,1
that is the coeficients

for (a+b)^5 that is
1a^5b^0+5a^4b^1+10a^3b^2+10a^2b^3+5a^1b^4+1a^0b^5
see the exponents each time add to 5

so
1x^5(-5)^0+5x^4(-5)^1+10x^3(-5)^2+10x^2(-5)^3+5x^1(-5)^4+1x^0(-5)^5=
x^5-25x^4+250x^3-1250

5 0

3 years ago

How would I start to solve number 15? Would I use distributive property?

natita [175]

$-5-x=2x-(4x+6)$

Using the distributive property is the correct first step. $(4x+6)$ is being multiplied by -1, so distributing gives

$-5-x=2x+(-4x-6)$
$-5-x=2x+((-4x)+(-6))$

Now, using the associative property of addition, you get

$-5-x=(2x+(-4x))+(-6)$
$-5-x=(2x-4x)-6$

Simplify the right hand side:

$-5-x=-2x-6$

Add 5 and $2x$ to both sides.

$(2x+5)-5-x=(2x+5)-2x-6$

On the left side, use the associative property. On the right, commutativity and associativity:

$2x+(5-5)-x=5+(2x-2x)-6$

Simplify.

$2x-x=-1$
$x=-1$