How many real solutions does the system have? Y= -3x-1 Y= x^2 -3x + 4
2 answers:
Answer:
No real solution of the given system.
Step-by-step explanation:
In this question the given equations are y = -3x - 1 and y = x²- 3x + 4.
We have to find the real solutions of the given system.
We will place the value of y from equation 1 to equation 2.
-3x - 1 = x² - 3x + 4
x² -3x + 3x + 4 + 1 = 0
x² + 5 =0
x² = -5
x = √(-5)
Therefore there is no real value of x.
Similarly the value of y of is also not defined.
Therefore there is no real solution for the system which we can see from the graph attached.
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