Danny brought a car for £10000 the value of the car depreciated by 20% in the first year then the value of the car depreciated b
1 answer:
£7200
In first year depreciates by 20%, that is it is worth 80% of it's original value
80% = = 0.8
value after 1 year = 0.8 × £10000 = £8000
In the second year it depreciates by 10% of it's value, that is it is worth 90% of it's value at the end of the first year.
90% = = 0.9
value after 2 years = 0.9 × £8000 = £7200
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I don't see a table but I can give you the means to answer it yourself. The inverse function is represented by this: 
where k is your constant. You are given a k value of 4. If you solve this for k then you will get xy=4. In your tables, multiply your x value by your y value within your coordinate points and if you get a product of 4 each time you multiply x by y, then that table is your answer.