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Wewaii [24]
3 years ago
13

A car travels at a speed of 64 km/h. Find the distance travelled in 4½ hours. ​

Mathematics
1 answer:
nordsb [41]3 years ago
6 0
Answer: 160m

Explanation: I hope this helps <3
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Suppose that g(x) = f(x) + 2. Which statement best compares the graph of g(x) with the graph of f(x)?
Jlenok [28]

Answer:

<u>A</u>

Step-by-step explanation:

Since it mentions g(x) is f(x) + 2, it means the y-intercept of g(x) is 2 more than that of f(x).

This basically means that :

<u><em>The graph of g(x) is shifted 2 units up.</em></u>

6 0
2 years ago
What is the degree of -8mn^2
jek_recluse [69]

Answer: 2

Step-by-step explanation:

To find the degree, use the exponent. An exponent of two means a degree of two, like an exponent of four means a degree of four

5 0
3 years ago
Question 3 Determine the leg lengths between the two points: (6, -3) and (-2,4).
Shalnov [3]

Answer:

9

Step-by-step explanation:

→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:

\begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}

a

2

+b

2

=c

2

x

2

+(x−3)

2

=(x+3)

2

x^2+x^2-6x+9=x^2+6x+9x

2

+x

2

−6x+9=x

2

+6x+9

→Subtract x^2-6x+9x

2

−6x+9 from both sides:

x^2 = 12xx

2

=12x

→Subtract 12x from both sides:

x^2 -12x=0x

2

−12x=0

→Factor out x:

x(x-12)=0x(x−12)=0

→Separate, set = to 0, and solve:

\begin{gathered}x = 0\\x -12=0\end{gathered}

x=0

x−12=0

→ Add 12 to both sides: x = 12x=12

→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.

→All we need to do is take 12, and plug it into the equation for the shortest leg.

\begin{gathered}x - 3=?\\12-3=9\end{gathered}

x−3=?

12−3=9

3 0
3 years ago
Find the value of the power.<br><br> 3 5 = _____
SVETLANKA909090 [29]

Answer: 243

Step-by-step explanation:

7 0
3 years ago
URGENT HELP Graph f(x) = 3|x - 5| + 1 (please put picture of the answer graphed)
charle [14.2K]

Answer:

Step-by-step explanation:

I uploaded a picture of the graph, but you can go to the site, Desmos. Just plug in your equation, and you will get the equation graphed.

6 0
2 years ago
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