3 years ago

What is the slope of a line perpendicular to the line with equation y = 1/6 (x) – 2

1 answer:

3 0

Let gradient of original line = m = 1/6
Gradient of line perpendicular to this = -1/m = -6

(Gradient = slope)

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Harman [31]

Answer:

-14

Step-by-step explanation:

a-4c=(-6)-4(2)=-6-8=-14. Hope this helps!

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3 years ago

Artemon [7]

${5}^{2} + {x}^{2} = {8}^{2}$

$25 + {x}^{2} = 64$

Subtract both sides 25

$25 - 25 + {x}^{2} = 64 - 25$

${x}^{2} = 39$

Thus :

$x = \sqrt{39}$

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I am Lyosha [343]

4x/4= x
4y/4 = y
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xenn [34]

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Snezhnost [94]

I believe it's the first option. Hope this helps.

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3 years ago