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gizmo_the_mogwai [7]
3 years ago
10

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

s then done to see if the mean time has increased in the new century. A random sample of 26 first-time convicted burglars in a recent year was picked. The mean length of time in jail from the survey was 3 years with a standard deviation of 1.8 years.Suppose that it is somehow known that the population standard deviation is 1.5. If you were conducting a hypothesis test to determine if the mean length of jail time has increased, what would the null and alternative hypotheses be? The distribution of the population is normal.(a) null hypothesis H0: μ = 2.5 yearsH0: μ = 3 years H0: μ > 3 yearsH0: μ ≥ 2.5 yearsH0: μ = 1.8 years(b) alternative hypothesis Ha: μ ≠ 2.5 yearsHa: μ > 3 years Ha: μ ≥ 1.8 yearsHa: μ ≤ 3 yearsHa: μ > 2.5 years
Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

The null hypothesis is H_0: \mu = 2.5.

The alternative hypothesis is H_1: \mu > 2.5

Step-by-step explanation:

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years.

At the null hypothesis, we test if the mean is of 2.5 years, that is:

H_0: \mu = 2.5

A study was then done to see if the mean time has increased in the new century.

At the alternative hypothesis, we test if the mean has increased, that is, if it is above 2.5 years. So

H_1: \mu > 2.5

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Find the least common multiple of each pair of polynomials.<br> 5 y² - 80 and y + 4
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The least common multiple of each pair of the polynomial (5y² - 80) and

(y + 4) is equal to 5(y-4)(y+4).

As given in the question,

Given pair of the polynomial is (5y² - 80) and (y + 4)

Simplify the given polynomial using (a² -b²) = (a-b)(a +b)

(5y² - 80) = 5(y² -16)

⇒(5y² - 80) = 5(y² - 4²)

⇒(5y² - 80) = 5(y -4)(y + 4)

And  (y + 4) = (1) (y+4)

Least common multiple = 5(y-4)(y+ 4)

Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).

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How do you work out the circumference of a circle using diameter?
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3 years ago
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

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Integration

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Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

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We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
3 years ago
What is the equation of a line that is parallel to -x+3y=6 and passes through the point (3,5)?
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For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

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b: It is the cut-off point with the y axis

By definition, if two lines are parallel then their slopes are equal.

We have the following line:

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Thus, the slope is:m_ {1} = \frac {1} {3}

Then m_ {2} = \frac {1} {3}

So, the line is of the form:

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We substitute the point(x, y) :( 3,5)and find b:

5 = \frac {1} {3} (3) + b\\5 = b

Thus, the equation is:

y = \frac {1} {3} x + 5

Answer:

y = \frac {1} {3} x + 5

5 0
3 years ago
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