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2 years ago

Please help me. This was my study page but this was hard.

Mathematics

1 answer:

iVinArrow [24]2 years ago

3 0

Your answer is 3277 because a negative divided by a negitive makes it a positive.

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Amanda exercised for 10 minutes every day in the first week, 20 minutes in the second week, 30 minutes in the third week, and 40

Dominik [7]

Amanda's method is linear because the number of minutes increased by an equal number every week.

7 0

2 years ago

Need help with his geometry question. Find the value of x

GREYUIT [131]

Answer: 3

Step-by-step explanation:

5 0

2 years ago

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

7 0

3 years ago

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

katrin2010 [14]

2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
x = -(3 / 4) + sq root (-36) / 4
x = -(3 / 4) - sq root (-36) / 4

7 0

2 years ago

What is the sum of all the integers between the square root of 10 and the square root of 47

insens350 [35]

First estimate the square root of 10, about 3.16
and then the square root of 47, about 6.85
now what are the integers in between 3.16 and 6.85:
4,5,6
now add them all
4+5+6
=15
Hope this helps.

5 0

3 years ago

Read 2 more answers