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Monica [59]
4 years ago
15

Which expression is equivalent to p·q·q·q·q·q·q·q·q·q?

Mathematics
2 answers:
Sergeeva-Olga [200]4 years ago
8 0

\huge{\boxed{pq^9}}

An exponent is multiplying the same thing by itself a number of times.

For example, 10^2\ =\ 10*10\ =\ 100

There is one p. p^1

There are nine qs. q^9

This leaves us with p^1 * q^9, or p^1 q^9.

We don't need a power of one, so we can just keep p*q^9, or \boxed{pq^9}

Vlad1618 [11]4 years ago
7 0

Answer:

1. pq^9.

Step-by-step explanation:

We have the product of 1 p and 9 q's.

So it is pq^9.

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Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

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Let Fi represent event of failure rate. So from the question,

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Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
4 years ago
I WILL MARK BRAINLIEST
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Answer:

I believe the answer is A. 15-(3xy)

Step-by-step explanation:

The expression you are given is 15-(yx3) and option A is 15-(3xy). All they did was flip the values in the parentheses. It doesen't matter what value is first because the negative sign will be distributed to everything in the parentheses.

Hope this helps!!

Mark me brainliest please!

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