In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
<span>slope
m = (1 - 1)/(0 + 2) = 0
(x1, y1) as (-2, 1)
</span><span>point-slope form</span><span>
y - y1 = m(x - x1)
y - 1 = 0(x + 2)
y - 1 = 0
y = 1</span>
Answer:
- 6.56- 6.6
- 6.723- 6.7
- 6.538- 6.5
- 6.647- 6.6
- 6.49- 6.5
- 6.687- 6.7
<em>Hope this helps and would appreciate if you would add me as brainiest</em>
