Question

Write the equation of the line that passes through

Answer 1

The equation of line which passes through  the points (-1, 2) and (6, 3) in slope-intercept form is:

$y = \frac{1}{7}x+\frac{15}{7}$

Further explanation:

Given

(x1,y1) = (-1,2)

(x2, y2) = (6,3)

We know that the general form of equation is:

y = mx+b

We have to calculate the slope first

$m = \frac{y_2-y_1}{x_2-x_1}\\ = \frac{3-2}{6-(-1)}\\ =\frac{1}{7}$

The equation will be:

$y = \frac{1}{7}x+b$

We have to find the value of b. For which we have to put any one point in the equation

$3 = \frac{1}{7}(6)+b\\ 3 = \frac{6}{7} +b\\ 3 - \frac{6}{7} = b\\b = \frac{21-6}{7} \\b = \frac{15}{7}$

The equation of line is:

$y = \frac{1}{7}x+\frac{15}{7}$

Keywords: Equation of line with two points, Point-slope form

Learn more about point-slope form of line at:

• brainly.com/question/10480770
• brainly.com/question/1284310

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