Question

What is the differentiation of (sin3x-cos4x)(tan6x+sec8x)

Answer 1

Answer:

expanded:

y = sin(4x)*sin(4x)*cos(3x)

need to use the product rule and chain rule

look at individual derivatives, use chain rule

d/dx sin(4x) = 4cos(4x)

d/dx cos(3x) = -3sin(3x)

put it together using product rule

dy/dx = 4cos(4x)*sin(4x)*cos(3x) + 4cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin(4x)*sin(4x)

simplify

dy/dx = 8cos(4x)*sin(4x)*cos(3x) - 3sin(3x)*sin2(4x)

answer is A.

Hope it helps friend request me and I'll accept xx:)