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3 years ago

12

What is the zero of f(x)=-1.5x+60?

1 answer:

Marianna [84]3 years ago

7 0

I’m pretty sure it’s x=40

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Can you always show that a prediction based on theoretical probability is true by performing the event often enough? If so, expl

svetoff [14.1K]

I don't know I am just trying to get my questions answered

8 0

4 years ago

Please can I have an explanation also, I am terrible at these kinds of questions!

wlad13 [49]

Answer:

<em>The fraction of the beads that are red is</em>

Step-by-step explanation:

<u>Algebraic Expressions</u>

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

$\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]$

Knowing that:

$\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]$

$\displaystyle \frac{y}{b}=\frac{5}{4}$

Multiplying the equations above:

$\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}$

Simplifying:

$\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]$

Dividing [1] by r:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}$

Substituting from [2] and [3]:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}$

Operating:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}$

The fraction of the beads that are red is $\mathbf{\frac{10}{37}}$

8 0

3 years ago

150 pounds shared into the ratio of 4:1

V125BC [204]

$\begin{cases}x+y=150\smallskip\\\dfrac{x}{y}=\dfrac{4}{1}\end{cases}\Leftrightarrow\begin{cases}x+y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}5y=150\smallskip\\x=4y\end{cases}\Leftrightarrow\begin{cases}y=30\smallskip\\x=120\end{cases}$

$150=120+30$

4 0

3 years ago

Anyone know how to solve this??

Tom [10]

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

7 0

4 years ago

What is the mean absolute deviation for the set of data below?<br><br> 2, 8, 10, 16

Evgesh-ka [11]

Solution: We are given below data:

$2, 8, 10, 16$

Now to find the mean deviation, we use the below formula:

$MD= \frac{\sum|X-\bar{X}|}{N}$

Where:

$\sum,$ represents the summation

X, represents the observation.

$\bar{X},$ represents the mean

N represents the number of observation.

$\bar{X}= \frac{\sum{X}}{N}= \frac{2+8+10+16}{4}=9$

$\sum |X-\bar{X}| = |2-9| + |8-9| +|10-9| +|16-9|=7+1+1+7=16$

Therefore, the mean deviation is:

$MD= \frac{16}{4}$

= 4

5 0

4 years ago

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